Practise Markdown Math typing and formatting by reproducing:

Suppose we want to publish something that is as simple as

To have numbered equation, type:

$$1+1=2\tag{1}$$

Pay attention to the \tag{1}. Unlike LaTex, you have to manage numbering and reference yourself in Markdown.

$$1+1=2\tag{1}$$

This is not very impressive. If we want our article to be accepted by IEEE reviewers, we have to be more abstract. So, we could complicate the left hand side of the expression by using

To have text in between equations in the same line, type:

$$\ln(e) = 1 \text{  and  } \sin^2x + \cos^2 x = 1$$

Pay attention to the space before and after the and in the {}.

$$\ln(e) = 1 \text{ and } \sin^2x + \cos^2 x = 1$$

and the right hand side can be stated as

This one is similar to LaTex, type:

$$2=\sum_{n=1}^\infty\frac{1}{2^n}$$

$$2=\sum_{n=1}^\infty\frac{1}{2^n}$$

Therefore, Equation (1) can be expressed more scientificially as:

Type

$$\ln(e) + (\sin^2x + \cos^2 x) = \sum_{n=1}^\infty\frac{1}{2^n} \tag{2}$$

Pay attention to the \tag{2}.

$$\ln(e) + (\sin^2x + \cos^2 x) = \sum_{n=1}^\infty\frac{1}{2^n} \tag{2}$$

which is far more impressive. However, we should not stop here. The expression can be further complicated by using

Type

$$e = \lim_{z\rightarrow\infty}(1+\frac{1}{z})^z \text{ and } 1=\cosh(y)\sqrt{1-\tanh^2y}$$

Pay attention to the space before and after and, again.

$$e = \lim_{z\rightarrow\infty}(1+\frac{1}{z})^z \text{ and } 1=\cosh(y)\sqrt{1-\tanh^2y}$$

Equation (2) may therefore be written as

This equation is “impressive”,

$$\ln\left[\lim_{z\rightarrow\infty}(1+\frac{1}{z})^z\right] + \left(\sin^2x + \cos^2 x\right) = \sum_{n=1}^\infty \frac{\cosh(y)\sqrt{1-\tanh^2y}}{2^n} \tag{3}$$

Pay attention to the first pair of brackets []: it comes with \left[ and \right]. Without \left and \right, the bracket will be smaller or shorter, which won’t contain the full height of $\lim_{z\rightarrow\infty}(1+\frac{1}{z})^z$.

$$\ln\left[\lim_{z\rightarrow\infty}(1+\frac{1}{z})^z\right] + \left(\sin^2x + \cos^2 x\right) = \sum_{n=1}^\infty \frac{\cosh(y)\sqrt{1-\tanh^2y}}{2^n} \tag{3}$$

Note: Other methods of a similar nature could also be used to enhance our prestige, once we grasp the underlying pringciples.